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143413341221 = 459131237931
BaseRepresentation
bin1000010110010000011…
…0011110110000100101
3111201011201111120122102
42011210012132300211
54322202303404341
6145514433341445
713234626200303
oct2054406366045
9451151446572
10143413341221
11559041019a7
1223964a07885
13106a6aa9427
146d26aad273
153ae5711c9b
hex216419ec25

143413341221 has 4 divisors (see below), whose sum is σ = 143444583744. Its totient is φ = 143382098700.

The previous prime is 143413341199. The next prime is 143413341233. The reversal of 143413341221 is 122143314341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143413341221 - 214 = 143413324837 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143413341271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15614375 + ... + 15623556.

It is an arithmetic number, because the mean of its divisors is an integer number (35861145936).

Almost surely, 2143413341221 is an apocalyptic number.

It is an amenable number.

143413341221 is a deficient number, since it is larger than the sum of its proper divisors (31242523).

143413341221 is an equidigital number, since it uses as much as digits as its factorization.

143413341221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31242522.

The product of its digits is 6912, while the sum is 29.

Adding to 143413341221 its reverse (122143314341), we get a palindrome (265556655562).

The spelling of 143413341221 in words is "one hundred forty-three billion, four hundred thirteen million, three hundred forty-one thousand, two hundred twenty-one".

Divisors: 1 4591 31237931 143413341221