Base | Representation |
---|---|
bin | 1000010110010000011… |
… | …0011110110000100101 |
3 | 111201011201111120122102 |
4 | 2011210012132300211 |
5 | 4322202303404341 |
6 | 145514433341445 |
7 | 13234626200303 |
oct | 2054406366045 |
9 | 451151446572 |
10 | 143413341221 |
11 | 559041019a7 |
12 | 23964a07885 |
13 | 106a6aa9427 |
14 | 6d26aad273 |
15 | 3ae5711c9b |
hex | 216419ec25 |
143413341221 has 4 divisors (see below), whose sum is σ = 143444583744. Its totient is φ = 143382098700.
The previous prime is 143413341199. The next prime is 143413341233. The reversal of 143413341221 is 122143314341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 143413341221 - 214 = 143413324837 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143413341271) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15614375 + ... + 15623556.
It is an arithmetic number, because the mean of its divisors is an integer number (35861145936).
Almost surely, 2143413341221 is an apocalyptic number.
It is an amenable number.
143413341221 is a deficient number, since it is larger than the sum of its proper divisors (31242523).
143413341221 is an equidigital number, since it uses as much as digits as its factorization.
143413341221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31242522.
The product of its digits is 6912, while the sum is 29.
Adding to 143413341221 its reverse (122143314341), we get a palindrome (265556655562).
The spelling of 143413341221 in words is "one hundred forty-three billion, four hundred thirteen million, three hundred forty-one thousand, two hundred twenty-one".
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