Base | Representation |
---|---|
bin | 10001110010001010110… |
… | …101111111011000101011 |
3 | 11022211110020222120211022 |
4 | 101302022311333120223 |
5 | 130010330112334011 |
6 | 2333231450523055 |
7 | 154202531430041 |
oct | 21621265773053 |
9 | 4284406876738 |
10 | 1222100121131 |
11 | 43132072720a |
12 | 178a26a3648b |
13 | 8b3220c3666 |
14 | 432156cc391 |
15 | 21bc9ee48db |
hex | 11c8ad7f62b |
1222100121131 has 2 divisors, whose sum is σ = 1222100121132. Its totient is φ = 1222100121130.
The previous prime is 1222100121119. The next prime is 1222100121149. The reversal of 1222100121131 is 1311210012221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1222100121131 - 214 = 1222100104747 is a prime.
It is a super-2 number, since 2×12221001211312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1222100121101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611050060565 + 611050060566.
It is an arithmetic number, because the mean of its divisors is an integer number (611050060566).
Almost surely, 21222100121131 is an apocalyptic number.
1222100121131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222100121131 is an equidigital number, since it uses as much as digits as its factorization.
1222100121131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1222100121131 its reverse (1311210012221), we get a palindrome (2533310133352).
The spelling of 1222100121131 in words is "one trillion, two hundred twenty-two billion, one hundred million, one hundred twenty-one thousand, one hundred thirty-one".
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