Base | Representation |
---|---|
bin | 111000111010001001… |
… | …0100010001100001111 |
3 | 102200110000212022201101 |
4 | 1301310102202030033 |
5 | 4000241241144413 |
6 | 132050442323531 |
7 | 11554323465406 |
oct | 1616422421417 |
9 | 380400768641 |
10 | 122210099983 |
11 | 47913462a34 |
12 | 1b827ab95a7 |
13 | b6a8043c3a |
14 | 5cb4a9263d |
15 | 32a4019edd |
hex | 1c744a230f |
122210099983 has 2 divisors, whose sum is σ = 122210099984. Its totient is φ = 122210099982.
The previous prime is 122210099911. The next prime is 122210100029. The reversal of 122210099983 is 389990012221.
It is an a-pointer prime, because the next prime (122210100029) can be obtained adding 122210099983 to its sum of digits (46).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122210099983 - 213 = 122210091791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122210094983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61105049991 + 61105049992.
It is an arithmetic number, because the mean of its divisors is an integer number (61105049992).
Almost surely, 2122210099983 is an apocalyptic number.
122210099983 is a deficient number, since it is larger than the sum of its proper divisors (1).
122210099983 is an equidigital number, since it uses as much as digits as its factorization.
122210099983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 46.
The spelling of 122210099983 in words is "one hundred twenty-two billion, two hundred ten million, ninety-nine thousand, nine hundred eighty-three".
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