Base | Representation |
---|---|
bin | 1011000111010111001110… |
… | …1101101101100100110011 |
3 | 1121021022212002121122001022 |
4 | 2301311303231231210303 |
5 | 3100212330032220430 |
6 | 41554150114130055 |
7 | 2400642554144123 |
oct | 261656355554463 |
9 | 47238762548038 |
10 | 12221123320115 |
11 | 3991a49568056 |
12 | 145465158092b |
13 | 6a85a7040a38 |
14 | 303711234c83 |
15 | 162d75a514e5 |
hex | b1d73b6d933 |
12221123320115 has 8 divisors (see below), whose sum is σ = 14942052663408. Its totient is φ = 9592428869920.
The previous prime is 12221123320031. The next prime is 12221123320123. The reversal of 12221123320115 is 51102332112221.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12221123320115 - 214 = 12221123303731 is a prime.
It is a super-2 number, since 2×122211233201152 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23058722981 + ... + 23058723510.
It is an arithmetic number, because the mean of its divisors is an integer number (1867756582926).
Almost surely, 212221123320115 is an apocalyptic number.
12221123320115 is a deficient number, since it is larger than the sum of its proper divisors (2720929343293).
12221123320115 is an equidigital number, since it uses as much as digits as its factorization.
12221123320115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46117446549.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 12221123320115 its reverse (51102332112221), we get a palindrome (63323455432336).
The spelling of 12221123320115 in words is "twelve trillion, two hundred twenty-one billion, one hundred twenty-three million, three hundred twenty thousand, one hundred fifteen".
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