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122433502135 = 5723152091307
BaseRepresentation
bin111001000000110011…
…0101111101110110111
3102201000121020022212011
41302001212233232313
54001220434032020
6132124542505051
711563005411550
oct1620146575667
9381017208764
10122433502135
1147a1857a30a
121b88a895187
13b712403069
145cd6607327
1532b894835a
hex1c819afbb7

122433502135 has 16 divisors (see below), whose sum is σ = 175209186816. Its totient is φ = 80304209568.

The previous prime is 122433502111. The next prime is 122433502229. The reversal of 122433502135 is 531205334221.

It is a cyclic number.

It is not a de Polignac number, because 122433502135 - 27 = 122433502007 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 122433502097 and 122433502106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 76044849 + ... + 76046458.

It is an arithmetic number, because the mean of its divisors is an integer number (10950574176).

Almost surely, 2122433502135 is an apocalyptic number.

122433502135 is a deficient number, since it is larger than the sum of its proper divisors (52775684681).

122433502135 is a wasteful number, since it uses less digits than its factorization.

122433502135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 152091342.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 122433502135 its reverse (531205334221), we get a palindrome (653638836356).

The spelling of 122433502135 in words is "one hundred twenty-two billion, four hundred thirty-three million, five hundred two thousand, one hundred thirty-five".

Divisors: 1 5 7 23 35 115 161 805 152091307 760456535 1064639149 3498100061 5323195745 17490500305 24486700427 122433502135