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12250331202119 is a prime number
BaseRepresentation
bin1011001001000100000010…
…1000111100001001000111
31121101010020122101202210212
42302101000220330021013
53101202134241431434
642015420252310035
72403025425065063
oct262210050741107
947333218352725
1012250331202119
1139a337766410a
12145a24317231b
136ab28028275a
14304cc23a6aa3
151639d4d5d8ce
hexb2440a3c247

12250331202119 has 2 divisors, whose sum is σ = 12250331202120. Its totient is φ = 12250331202118.

The previous prime is 12250331202113. The next prime is 12250331202121. The reversal of 12250331202119 is 91120213305221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12250331202119 - 24 = 12250331202103 is a prime.

It is a super-2 number, since 2×122503312021192 (a number of 27 digits) contains 22 as substring.

Together with 12250331202121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12250331202113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6125165601059 + 6125165601060.

It is an arithmetic number, because the mean of its divisors is an integer number (6125165601060).

Almost surely, 212250331202119 is an apocalyptic number.

12250331202119 is a deficient number, since it is larger than the sum of its proper divisors (1).

12250331202119 is an equidigital number, since it uses as much as digits as its factorization.

12250331202119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 32.

The spelling of 12250331202119 in words is "twelve trillion, two hundred fifty billion, three hundred thirty-one million, two hundred two thousand, one hundred nineteen".