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1225113120 = 2533571129127
BaseRepresentation
bin100100100000101…
…1011111000100000
310011101021012021000
41021001123320200
510002112104440
6321322232000
742234201240
oct11101337040
93141235230
101225113120
115795a9690
122a2355600
13166a7800a
14b89c9b20
157284b730
hex4905be20

1225113120 has 768 divisors, whose sum is σ = 5573836800. Its totient is φ = 243855360.

The previous prime is 1225113079. The next prime is 1225113121. The reversal of 1225113120 is 213115221.

1225113120 is a `hidden beast` number, since 122 + 511 + 31 + 2 + 0 = 666.

It is a super-2 number, since 2×12251131202 = 3001804313592268800, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1225113093 and 1225113102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1225113121) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 9646497 + ... + 9646623.

It is an arithmetic number, because the mean of its divisors is an integer number (7257600).

Almost surely, 21225113120 is an apocalyptic number.

1225113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1225113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2786918400).

1225113120 is an abundant number, since it is smaller than the sum of its proper divisors (4348723680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1225113120 is a wasteful number, since it uses less digits than its factorization.

1225113120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 198 (or 184 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

The square root of 1225113120 is about 35001.6159626952. The cubic root of 1225113120 is about 1070.0204147850.

Adding to 1225113120 its reverse (213115221), we get a palindrome (1438228341).

The spelling of 1225113120 in words is "one billion, two hundred twenty-five million, one hundred thirteen thousand, one hundred twenty".