Base | Representation |
---|---|
bin | 10001110101000011110… |
… | …011101110101100010001 |
3 | 11100010110112012002101020 |
4 | 101311003303232230101 |
5 | 130033204022012200 |
6 | 2334503423030053 |
7 | 154342452221640 |
oct | 21650363565421 |
9 | 4303415162336 |
10 | 1225203313425 |
11 | 432673369543 |
12 | 17955213b329 |
13 | 8b6c7c98710 |
14 | 4342b8b7357 |
15 | 21d0c66dea0 |
hex | 11d43ceeb11 |
1225203313425 has 96 divisors (see below), whose sum is σ = 2493943710720. Its totient is φ = 516840480000.
The previous prime is 1225203313357. The next prime is 1225203313441. The reversal of 1225203313425 is 5243133025221.
It is not a de Polignac number, because 1225203313425 - 217 = 1225203182353 is a prime.
It is a super-2 number, since 2×12252033134252 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 22160466 + ... + 22215684.
It is an arithmetic number, because the mean of its divisors is an integer number (25978580320).
Almost surely, 21225203313425 is an apocalyptic number.
1225203313425 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1225203313425 is an abundant number, since it is smaller than the sum of its proper divisors (1268740397295).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1225203313425 is a wasteful number, since it uses less digits than its factorization.
1225203313425 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58503 (or 58498 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 1225203313425 its reverse (5243133025221), we get a palindrome (6468336338646).
The spelling of 1225203313425 in words is "one trillion, two hundred twenty-five billion, two hundred three million, three hundred thirteen thousand, four hundred twenty-five".
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