1225340433 has 64 divisors (see below), whose sum is σ = 2060536320. Its totient is φ = 715309056.

The previous prime is 1225340423. The next prime is 1225340437. The reversal of 1225340433 is 3340435221.

1225340433 is a `hidden beast` number, since 1 + 2 + 253 + 404 + 3 + 3 = 666.

It is a de Polignac number, because none of the positive numbers 2^k-1225340433 is a prime.

It is a super-3 number, since 3×1225340433³ (a number of 28 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1225340397 and 1225340406.

It is not an unprimeable number, because it can be changed into a prime (1225340437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 389041 + ... + 392177.

It is an arithmetic number, because the mean of its divisors is an integer number (32195880).

Almost surely, 2^1225340433 is an apocalyptic number.

It is an amenable number.

1225340433 is a deficient number, since it is larger than the sum of its proper divisors (835195887).

1225340433 is a wasteful number, since it uses less digits than its factorization.

1225340433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3223 (or 3217 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 27.

The square root of 1225340433 is about 35004.8629907332. The cubic root of 1225340433 is about 1070.0865894930.

Adding to 1225340433 its reverse (3340435221), we get a palindrome (4565775654).

The spelling of 1225340433 in words is "one billion, two hundred twenty-five million, three hundred forty thousand, four hundred thirty-three".