122540333 has 4 divisors (see below), whose sum is σ = 122803200. Its totient is φ = 122277468.

The previous prime is 122540323. The next prime is 122540347. The reversal of 122540333 is 333045221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 333045221 = 23 ⋅14480227.

It is a cyclic number.

It is not a de Polignac number, because 122540333 - 2⁴ = 122540317 is a prime.

It is a super-2 number, since 2×122540333² = 30032266423501778, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 122540299 and 122540308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122540323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130733 + ... + 131666.

It is an arithmetic number, because the mean of its divisors is an integer number (30700800).

Almost surely, 2^122540333 is an apocalyptic number.

It is an amenable number.

122540333 is a deficient number, since it is larger than the sum of its proper divisors (262867).

122540333 is an equidigital number, since it uses as much as digits as its factorization.

122540333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262866.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 122540333 is about 11069.7937198486. The cubic root of 122540333 is about 496.6986947400.

Adding to 122540333 its reverse (333045221), we get a palindrome (455585554).

The spelling of 122540333 in words is "one hundred twenty-two million, five hundred forty thousand, three hundred thirty-three".