Base | Representation |
---|---|
bin | 1011001100001000010100… |
… | …1001001101111110110101 |
3 | 1121120011020121220020010022 |
4 | 2303002011021031332311 |
5 | 3103033041122401122 |
6 | 42055532430534525 |
7 | 2406602210365361 |
oct | 263020511157665 |
9 | 47504217806108 |
10 | 12303020122037 |
11 | 3a13755135527 |
12 | 14684a8667445 |
13 | 6b3229129848 |
14 | 30767dc842a1 |
15 | 16506a7ea642 |
hex | b308524dfb5 |
12303020122037 has 2 divisors, whose sum is σ = 12303020122038. Its totient is φ = 12303020122036.
The previous prime is 12303020121971. The next prime is 12303020122039. The reversal of 12303020122037 is 73022102030321.
It is a happy number.
12303020122037 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9660571557316 + 2642448564721 = 3108146^2 + 1625561^2 .
It is a cyclic number.
It is not a de Polignac number, because 12303020122037 - 28 = 12303020121781 is a prime.
Together with 12303020122039, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 12303020121997 and 12303020122015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12303020122039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151510061018 + 6151510061019.
It is an arithmetic number, because the mean of its divisors is an integer number (6151510061019).
Almost surely, 212303020122037 is an apocalyptic number.
It is an amenable number.
12303020122037 is a deficient number, since it is larger than the sum of its proper divisors (1).
12303020122037 is an equidigital number, since it uses as much as digits as its factorization.
12303020122037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 26.
Adding to 12303020122037 its reverse (73022102030321), we get a palindrome (85325122152358).
The spelling of 12303020122037 in words is "twelve trillion, three hundred three billion, twenty million, one hundred twenty-two thousand, thirty-seven".
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