Base | Representation |
---|---|
bin | 111001010100101010… |
… | …1101010000101110111 |
3 | 102202202001120120121122 |
4 | 1302221111222011313 |
5 | 4004102112024343 |
6 | 132315034334155 |
7 | 11615351452355 |
oct | 1625125520567 |
9 | 382661516548 |
10 | 123100111223 |
11 | 4822a892611 |
12 | 1ba35b8a35b |
13 | b7ba550bcb |
14 | 5d5ad6c7d5 |
15 | 3307222068 |
hex | 1ca956a177 |
123100111223 has 2 divisors, whose sum is σ = 123100111224. Its totient is φ = 123100111222.
The previous prime is 123100111177. The next prime is 123100111243. The reversal of 123100111223 is 322111001321.
It is a strong prime.
It is an emirp because it is prime and its reverse (322111001321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123100111223 - 218 = 123099849079 is a prime.
It is a super-2 number, since 2×1231001112232 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123100111243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61550055611 + 61550055612.
It is an arithmetic number, because the mean of its divisors is an integer number (61550055612).
Almost surely, 2123100111223 is an apocalyptic number.
123100111223 is a deficient number, since it is larger than the sum of its proper divisors (1).
123100111223 is an equidigital number, since it uses as much as digits as its factorization.
123100111223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 123100111223 its reverse (322111001321), we get a palindrome (445211112544).
The spelling of 123100111223 in words is "one hundred twenty-three billion, one hundred million, one hundred eleven thousand, two hundred twenty-three".
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