Search a number
-
+
123101300001300 = 2235273173251129449
BaseRepresentation
bin11011111111010111000001…
…010000100000101000010100
3121010212100222020212120011120
4123333113001100200220110
5112113342430300020200
61113451542335003540
734633526654224065
oct3377270120405024
9533770866776146
10123101300001300
1136250a71674225
1211981a343695b0
13538c530ba4a3a
1422581c590856c
15e372322c49a0
hex6ff5c1420a14

123101300001300 has 288 divisors, whose sum is σ = 364588771075200. Its totient is φ = 32061680640000.

The previous prime is 123101300001293. The next prime is 123101300001313. The reversal of 123101300001300 is 3100003101321.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 123101300001300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 950898976 + ... + 951028424.

It is an arithmetic number, because the mean of its divisors is an integer number (1265933232900).

Almost surely, 2123101300001300 is an apocalyptic number.

123101300001300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 123101300001300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (182294385537600).

123101300001300 is an abundant number, since it is smaller than the sum of its proper divisors (241487471073900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123101300001300 is a wasteful number, since it uses less digits than its factorization.

123101300001300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129963 (or 129956 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 123101300001300 its reverse (3100003101321), we get a palindrome (126201303102621).

The spelling of 123101300001300 in words is "one hundred twenty-three trillion, one hundred one billion, three hundred million, one thousand, three hundred".