Base | Representation |
---|---|
bin | 1011001100100011000100… |
… | …0110101100111111111111 |
3 | 1121120211210000022110111021 |
4 | 2303020301012230333333 |
5 | 3103142242212023403 |
6 | 42103121115005011 |
7 | 2410245143316166 |
oct | 263106106547777 |
9 | 47524700273437 |
10 | 12310200111103 |
11 | 3a167aa044594 |
12 | 1469971139767 |
13 | 6b3b0180169b |
14 | 307b616943dd |
15 | 16533ad198bd |
hex | b32311acfff |
12310200111103 has 2 divisors, whose sum is σ = 12310200111104. Its totient is φ = 12310200111102.
The previous prime is 12310200111091. The next prime is 12310200111119. The reversal of 12310200111103 is 30111100201321.
It is a happy number.
It is an a-pointer prime, because the next prime (12310200111119) can be obtained adding 12310200111103 to its sum of digits (16).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12310200111103 - 25 = 12310200111071 is a prime.
It is a super-3 number, since 3×123102001111033 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12310200111163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155100055551 + 6155100055552.
It is an arithmetic number, because the mean of its divisors is an integer number (6155100055552).
Almost surely, 212310200111103 is an apocalyptic number.
12310200111103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12310200111103 is an equidigital number, since it uses as much as digits as its factorization.
12310200111103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 12310200111103 its reverse (30111100201321), we get a palindrome (42421300312424).
The spelling of 12310200111103 in words is "twelve trillion, three hundred ten billion, two hundred million, one hundred eleven thousand, one hundred three".
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