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123131022001020 = 223351129714797527
BaseRepresentation
bin11011111111110010101100…
…110100111100001101111100
3121010222012200122001120212000
4123333302230310330031330
5112114334313113013040
61113513335520342300
734635631340111355
oct3377625464741574
9533865618046760
10123131022001020
113626263399a560
121198774a174990
1353922897a2717
142259805068d2c
15e37dc17d8130
hex6ffcacd3c37c

123131022001020 has 192 divisors, whose sum is σ = 432309544934400. Its totient is φ = 28820636248320.

The previous prime is 123131022001007. The next prime is 123131022001073. The reversal of 123131022001020 is 20100220131321.

123131022001020 is a `hidden beast` number, since 1 + 2 + 31 + 310 + 220 + 0 + 102 + 0 = 666.

It is a super-2 number, since 2×1231310220010202 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 123131022000984 and 123131022001002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 357226504 + ... + 357571023.

It is an arithmetic number, because the mean of its divisors is an integer number (2251612213200).

Almost surely, 2123131022001020 is an apocalyptic number.

123131022001020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

123131022001020 is an abundant number, since it is smaller than the sum of its proper divisors (309178522933380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123131022001020 is a wasteful number, since it uses less digits than its factorization.

123131022001020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 714797585 (or 714797577 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 123131022001020 its reverse (20100220131321), we get a palindrome (143231242132341).

The spelling of 123131022001020 in words is "one hundred twenty-three trillion, one hundred thirty-one billion, twenty-two million, one thousand, twenty".