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12313321020000 = 25325471113371847
BaseRepresentation
bin1011001100101110101100…
…1000000001101001100000
31121121010211111212001122200
42303023223020001221200
53103220140140120000
642104354522533200
72410415400520020
oct263135310015140
947533744761580
1012313321020000
113a18060787640
12146a4a2367200
136b41ab26a740
14307d79d71a80
1516546ece3500
hexb32eb201a60

12313321020000 has 2880 divisors, whose sum is σ = 60369804278784. Its totient is φ = 2296719360000.

The previous prime is 12313321019981. The next prime is 12313321020019. The reversal of 12313321020000 is 2012331321.

12313321020000 is a `hidden beast` number, since 1 + 231 + 332 + 102 + 0 + 0 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (12313321019981) and next prime (12313321020019).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 479 ways as a sum of consecutive naturals, for example, 6666659077 + ... + 6666660923.

Almost surely, 212313321020000 is an apocalyptic number.

12313321020000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12313321020000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (30184902139392).

12313321020000 is an abundant number, since it is smaller than the sum of its proper divisors (48056483258784).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12313321020000 is a wasteful number, since it uses less digits than its factorization.

12313321020000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1951 (or 1925 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 12313321020000 its reverse (2012331321), we get a palindrome (12315333351321).

The spelling of 12313321020000 in words is "twelve trillion, three hundred thirteen billion, three hundred twenty-one million, twenty thousand".