Base | Representation |
---|---|
bin | 111001011010101000… |
… | …0001100000010101101 |
3 | 102210020222201011222022 |
4 | 1302311100030002231 |
5 | 4010004300112023 |
6 | 132350534555525 |
7 | 11623326512234 |
oct | 1626520140255 |
9 | 383228634868 |
10 | 123300004013 |
11 | 48322701a6a |
12 | 1ba90b08ba5 |
13 | b81ca9b474 |
14 | 5d79723b1b |
15 | 3319a597c8 |
hex | 1cb540c0ad |
123300004013 has 4 divisors (see below), whose sum is σ = 123372153180. Its totient is φ = 123227854848.
The previous prime is 123300004007. The next prime is 123300004039. The reversal of 123300004013 is 310400003321.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 310400003321 = 3673 ⋅84508577.
It can be written as a sum of positive squares in 2 ways, for example, as 81611348329 + 41688655684 = 285677^2 + 204178^2 .
It is a cyclic number.
It is not a de Polignac number, because 123300004013 - 230 = 122226262189 is a prime.
It is a super-2 number, since 2×1233000040132 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 123300003982 and 123300004000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123300004073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36072020 + ... + 36075437.
It is an arithmetic number, because the mean of its divisors is an integer number (30843038295).
Almost surely, 2123300004013 is an apocalyptic number.
It is an amenable number.
123300004013 is a deficient number, since it is larger than the sum of its proper divisors (72149167).
123300004013 is an equidigital number, since it uses as much as digits as its factorization.
123300004013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72149166.
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 123300004013 its reverse (310400003321), we get a palindrome (433700007334).
The spelling of 123300004013 in words is "one hundred twenty-three billion, three hundred million, four thousand, thirteen".
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