Base | Representation |
---|---|
bin | 11100000010010001011010… |
… | …001001010110101001001111 |
3 | 121011120111112220102110112121 |
4 | 130002101122021112221033 |
5 | 112130132313441110210 |
6 | 1114123521355113411 |
7 | 34654143316210246 |
oct | 3402213211265117 |
9 | 534514486373477 |
10 | 123301433535055 |
11 | 363189318502a6 |
12 | 119b4788742867 |
13 | 53a5376a78c69 |
14 | 2263b6d62995d |
15 | e3c5473246da |
hex | 70245a256a4f |
123301433535055 has 64 divisors (see below), whose sum is σ = 157096570208256. Its totient is φ = 92763092160000.
The previous prime is 123301433535031. The next prime is 123301433535083. The reversal of 123301433535055 is 550535334103321.
It is a happy number.
It is not a de Polignac number, because 123301433535055 - 27 = 123301433534927 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1212340705 + ... + 1212442405.
It is an arithmetic number, because the mean of its divisors is an integer number (2454633909504).
Almost surely, 2123301433535055 is an apocalyptic number.
123301433535055 is a deficient number, since it is larger than the sum of its proper divisors (33795136673201).
123301433535055 is a wasteful number, since it uses less digits than its factorization.
123301433535055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 102968.
The product of its (nonzero) digits is 1215000, while the sum is 43.
Adding to 123301433535055 its reverse (550535334103321), we get a palindrome (673836767638376).
The spelling of 123301433535055 in words is "one hundred twenty-three trillion, three hundred one billion, four hundred thirty-three million, five hundred thirty-five thousand, fifty-five".
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