Base | Representation |
---|---|
bin | 11100000010010100001100… |
… | …111111011011010101111000 |
3 | 121011120210022000102122110011 |
4 | 130002110030333123111320 |
5 | 112130204440104221040 |
6 | 1114125135222431304 |
7 | 34654310552205355 |
oct | 3402241477332570 |
9 | 534523260378404 |
10 | 123304434054520 |
11 | 3631a131535a54 |
12 | 119b5285592534 |
13 | 53a57345b2a74 |
14 | 2263d75d2962c |
15 | e3c67096c3ea |
hex | 70250cfdb578 |
123304434054520 has 64 divisors (see below), whose sum is σ = 280164246167520. Its totient is φ = 48837019267584.
The previous prime is 123304434054517. The next prime is 123304434054541. The reversal of 123304434054520 is 25450434403321.
It is a Harshad number since it is a multiple of its sum of digits (40).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1770414 + ... + 15803266.
Almost surely, 2123304434054520 is an apocalyptic number.
123304434054520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
123304434054520 is an abundant number, since it is smaller than the sum of its proper divisors (156859812113000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123304434054520 is a wasteful number, since it uses less digits than its factorization.
123304434054520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14035024 (or 14035020 counting only the distinct ones).
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 123304434054520 its reverse (25450434403321), we get a palindrome (148754868457841).
The spelling of 123304434054520 in words is "one hundred twenty-three trillion, three hundred four billion, four hundred thirty-four million, fifty-four thousand, five hundred twenty".
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