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12331021131000 = 233253111313217253
BaseRepresentation
bin1011001101110000101000…
…1000100101110011111000
31121122211112001201212022100
42303130022020211303320
53104012412402143000
642120443133423400
72411613125134125
oct263341210456370
947584461655270
1012331021131000
113a24613a60a50
121471a0203ab60
136b5a6c30b8c0
14308b78a1774c
15165b58bb0a00
hexb370a225cf8

12331021131000 has 768 divisors, whose sum is σ = 49009186961280. Its totient is φ = 2756920320000.

The previous prime is 12331021130951. The next prime is 12331021131001. The reversal of 12331021131000 is 13112013321.

12331021131000 is a `hidden beast` number, since 1 + 2 + 331 + 0 + 21 + 1 + 310 + 0 + 0 = 666.

It is a super-2 number, since 2×123310211310002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12331021131001) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 1700123374 + ... + 1700130626.

Almost surely, 212331021131000 is an apocalyptic number.

12331021131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12331021131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24504593480640).

12331021131000 is an abundant number, since it is smaller than the sum of its proper divisors (36678165830280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12331021131000 is a wasteful number, since it uses less digits than its factorization.

12331021131000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8625 (or 8608 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 12331021131000 its reverse (13112013321), we get a palindrome (12344133144321).

The spelling of 12331021131000 in words is "twelve trillion, three hundred thirty-one billion, twenty-one million, one hundred thirty-one thousand".