123315411241335 has 8 divisors (see below), whose sum is σ = 197304657986160. Its totient is φ = 65768219328704.

The previous prime is 123315411241313. The next prime is 123315411241391. The reversal of 123315411241335 is 533142114513321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 123315411241335 - 2⁶ = 123315411241271 is a prime.

It is a super-2 number, since 2×123315411241335² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123315411241293 and 123315411241302.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4110513708030 + ... + 4110513708059.

It is an arithmetic number, because the mean of its divisors is an integer number (24663082248270).

Almost surely, 2^{123315411241335} is an apocalyptic number.

123315411241335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

123315411241335 is a deficient number, since it is larger than the sum of its proper divisors (73989246744825).

123315411241335 is an equidigital number, since it uses as much as digits as its factorization.

123315411241335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8221027416097.

The product of its digits is 129600, while the sum is 39.

Adding to 123315411241335 its reverse (533142114513321), we get a palindrome (656457525754656).

The spelling of 123315411241335 in words is "one hundred twenty-three trillion, three hundred fifteen billion, four hundred eleven million, two hundred forty-one thousand, three hundred thirty-five".