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12340041011 is a prime number
BaseRepresentation
bin10110111111000011…
…00001010100110011
31011211222222000220222
423133201201110303
5200233022303021
65400253523255
7614540421644
oct133741412463
934758860828
1012340041011
1152626a4501
1224847a352b
131218741a1c
14850c556cb
154c353d6ab
hex2df861533

12340041011 has 2 divisors, whose sum is σ = 12340041012. Its totient is φ = 12340041010.

The previous prime is 12340041001. The next prime is 12340041013. The reversal of 12340041011 is 11014004321.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (11014004321) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12340041011 is a prime.

It is a super-2 number, since 2×123400410112 (a number of 21 digits) contains 22 as substring.

Together with 12340041013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12340041013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6170020505 + 6170020506.

It is an arithmetic number, because the mean of its divisors is an integer number (6170020506).

Almost surely, 212340041011 is an apocalyptic number.

12340041011 is a deficient number, since it is larger than the sum of its proper divisors (1).

12340041011 is an equidigital number, since it uses as much as digits as its factorization.

12340041011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12340041011 its reverse (11014004321), we get a palindrome (23354045332).

The spelling of 12340041011 in words is "twelve billion, three hundred forty million, forty-one thousand, eleven".