Base | Representation |
---|---|
bin | 1011001110010011010000… |
… | …0101111001100011111111 |
3 | 1121200201111202210111002211 |
4 | 2303210310011321203333 |
5 | 3104140431120100020 |
6 | 42125021253401251 |
7 | 2412362336553220 |
oct | 263446405714377 |
9 | 47621452714084 |
10 | 12340315003135 |
11 | 3a28553120709 |
12 | 1473776639227 |
13 | 6b68c0922722 |
14 | 3093bb089247 |
15 | 165eeea8a85a |
hex | b39341798ff |
12340315003135 has 8 divisors (see below), whose sum is σ = 16923860575776. Its totient is φ = 8461930287840.
The previous prime is 12340315003123. The next prime is 12340315003157. The reversal of 12340315003135 is 53130051304321.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12340315003135 - 25 = 12340315003103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12340315003097 and 12340315003106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 176290214296 + ... + 176290214365.
It is an arithmetic number, because the mean of its divisors is an integer number (2115482571972).
Almost surely, 212340315003135 is an apocalyptic number.
12340315003135 is a deficient number, since it is larger than the sum of its proper divisors (4583545572641).
12340315003135 is an equidigital number, since it uses as much as digits as its factorization.
12340315003135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 352580428673.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 12340315003135 its reverse (53130051304321), we get a palindrome (65470366307456).
The spelling of 12340315003135 in words is "twelve trillion, three hundred forty billion, three hundred fifteen million, three thousand, one hundred thirty-five".
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