Base | Representation |
---|---|
bin | 1011001110010110010010… |
… | …1111011111100110111000 |
3 | 1121200210121122122020212201 |
4 | 2303211210233133212320 |
5 | 3104144114042310430 |
6 | 42125234251515544 |
7 | 2412421510332424 |
oct | 263454457374670 |
9 | 47623548566781 |
10 | 12341131213240 |
11 | 3a28931923415 |
12 | 1473963a58bb4 |
13 | 6b69c0a5c99b |
14 | 309457633b84 |
15 | 16604b5658ca |
hex | b3964bdf9b8 |
12341131213240 has 32 divisors (see below), whose sum is σ = 27767649419280. Its totient is φ = 4936433962752.
The previous prime is 12341131213223. The next prime is 12341131213343. The reversal of 12341131213240 is 4231213114321.
It is a junction number, because it is equal to n+sod(n) for n = 12341131213199 and 12341131213208.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16268887 + ... + 17010553.
Almost surely, 212341131213240 is an apocalyptic number.
12341131213240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12341131213240 is an abundant number, since it is smaller than the sum of its proper divisors (15426518206040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12341131213240 is a wasteful number, since it uses less digits than its factorization.
12341131213240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1157671 (or 1157667 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 12341131213240 its reverse (4231213114321), we get a palindrome (16572344327561).
The spelling of 12341131213240 in words is "twelve trillion, three hundred forty-one billion, one hundred thirty-one million, two hundred thirteen thousand, two hundred forty".
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