Base | Representation |
---|---|
bin | 111001100001110101… |
… | …1110100110101111101 |
3 | 102210212212022110110010 |
4 | 1303003223310311331 |
5 | 4011003241130140 |
6 | 132430544333433 |
7 | 11632326531105 |
oct | 1630353646575 |
9 | 383785273403 |
10 | 123542130045 |
11 | 48437347924 |
12 | 1bb3a014279 |
13 | b85acb4bc9 |
14 | 5d9d950205 |
15 | 3330e35880 |
hex | 1cc3af4d7d |
123542130045 has 32 divisors (see below), whose sum is σ = 199267263360. Its totient is φ = 65356312320.
The previous prime is 123542130017. The next prime is 123542130067. The reversal of 123542130045 is 540031245321.
It is not a de Polignac number, because 123542130045 - 26 = 123542129981 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 123542129994 and 123542130021.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4681227 + ... + 4707543.
It is an arithmetic number, because the mean of its divisors is an integer number (6227101980).
Almost surely, 2123542130045 is an apocalyptic number.
123542130045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
123542130045 is a deficient number, since it is larger than the sum of its proper divisors (75725133315).
123542130045 is a wasteful number, since it uses less digits than its factorization.
123542130045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28845.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 123542130045 its reverse (540031245321), we get a palindrome (663573375366).
The spelling of 123542130045 in words is "one hundred twenty-three billion, five hundred forty-two million, one hundred thirty thousand, forty-five".
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