12384093 has 4 divisors (see below), whose sum is σ = 16512128. Its totient is φ = 8256060.

The previous prime is 12384061. The next prime is 12384101. The reversal of 12384093 is 39048321.

12384093 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12384093 - 2⁵ = 12384061 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12384093.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12384023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2064013 + ... + 2064018.

It is an arithmetic number, because the mean of its divisors is an integer number (4128032).

Almost surely, 2^12384093 is an apocalyptic number.

It is an amenable number.

12384093 is a deficient number, since it is larger than the sum of its proper divisors (4128035).

12384093 is an equidigital number, since it uses as much as digits as its factorization.

12384093 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4128034.

The product of its (nonzero) digits is 5184, while the sum is 30.

The square root of 12384093 is about 3519.1040052832. The cubic root of 12384093 is about 231.3598895304.

The spelling of 12384093 in words is "twelve million, three hundred eighty-four thousand, ninety-three".