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12394660533 = 34131553511
BaseRepresentation
bin10111000101100011…
…11000001010110101
31011222210201222211020
423202301320022311
5200341013114113
65405524331353
7616102606353
oct134261701265
934883658736
1012394660533
11529050aa02
12249ab43b59
131226b56978
148581d27d3
154c822c023
hex2e2c782b5

12394660533 has 4 divisors (see below), whose sum is σ = 16526214048. Its totient is φ = 8263107020.

The previous prime is 12394660489. The next prime is 12394660547. The reversal of 12394660533 is 33506649321.

It is a happy number.

12394660533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12394660533 - 213 = 12394652341 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12394660133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2065776753 + ... + 2065776758.

It is an arithmetic number, because the mean of its divisors is an integer number (4131553512).

Almost surely, 212394660533 is an apocalyptic number.

It is an amenable number.

12394660533 is a deficient number, since it is larger than the sum of its proper divisors (4131553515).

12394660533 is an equidigital number, since it uses as much as digits as its factorization.

12394660533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4131553514.

The product of its (nonzero) digits is 349920, while the sum is 42.

The spelling of 12394660533 in words is "twelve billion, three hundred ninety-four million, six hundred sixty thousand, five hundred thirty-three".

Divisors: 1 3 4131553511 12394660533