Base | Representation |
---|---|
bin | 111001101111111000… |
… | …0011100000011110101 |
3 | 102212002200112021112222 |
4 | 1303133300130003311 |
5 | 4012434323220201 |
6 | 132545411052125 |
7 | 11650105653125 |
oct | 1633760340365 |
9 | 385080467488 |
10 | 124013101301 |
11 | 48659187571 |
12 | 2004b8a1045 |
13 | b90474511b |
14 | 600630ac85 |
15 | 335c46791b |
hex | 1cdfc1c0f5 |
124013101301 has 2 divisors, whose sum is σ = 124013101302. Its totient is φ = 124013101300.
The previous prime is 124013101279. The next prime is 124013101309. The reversal of 124013101301 is 103101310421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108300228100 + 15712873201 = 329090^2 + 125351^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-124013101301 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 124013101301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124013101309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62006550650 + 62006550651.
It is an arithmetic number, because the mean of its divisors is an integer number (62006550651).
Almost surely, 2124013101301 is an apocalyptic number.
It is an amenable number.
124013101301 is a deficient number, since it is larger than the sum of its proper divisors (1).
124013101301 is an equidigital number, since it uses as much as digits as its factorization.
124013101301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 124013101301 its reverse (103101310421), we get a palindrome (227114411722).
The spelling of 124013101301 in words is "one hundred twenty-four billion, thirteen million, one hundred one thousand, three hundred one".
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