Base | Representation |
---|---|
bin | 11100001100101000010101… |
… | …000111100001111100101100 |
3 | 121021002112211220212102212002 |
4 | 130030220111013201330230 |
5 | 112223313103420002200 |
6 | 1115430521310031432 |
7 | 35056442460301250 |
oct | 3414502507417454 |
9 | 537075756772762 |
10 | 124013240000300 |
11 | 365727a0a63a92 |
12 | 11aaa71b1a8578 |
13 | 54275242480c1 |
14 | 228a3b6970260 |
15 | e50d07b6dbd5 |
hex | 70ca151e1f2c |
124013240000300 has 72 divisors (see below), whose sum is σ = 318158105432160. Its totient is φ = 41052658752000.
The previous prime is 124013240000257. The next prime is 124013240000303. The reversal of 124013240000300 is 3000042310421.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (124013240000303) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3054493001 + ... + 3054533600.
Almost surely, 2124013240000300 is an apocalyptic number.
124013240000300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
124013240000300 is an abundant number, since it is smaller than the sum of its proper divisors (194144865431860).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
124013240000300 is a wasteful number, since it uses less digits than its factorization.
124013240000300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6109026651 (or 6109026644 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 124013240000300 its reverse (3000042310421), we get a palindrome (127013282310721).
The spelling of 124013240000300 in words is "one hundred twenty-four trillion, thirteen billion, two hundred forty million, three hundred", and thus it is an aban number.
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