Search a number
-
+
1240332113555 = 5601412756111
BaseRepresentation
bin10010000011001001100…
…011100001011010010011
311101120111212200202121222
4102003021203201122103
5130310200010113210
62345444541435255
7155416405003643
oct22031143413223
94346455622558
101240332113555
11439027162a47
1218047486bb2b
138cc69400062
1444064c68523
15223e5926655
hex120c98e1693

1240332113555 has 8 divisors (see below), whose sum is σ = 1490875076544. Its totient is φ = 990614664000.

The previous prime is 1240332113533. The next prime is 1240332113569. The reversal of 1240332113555 is 5553112330421.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1240332113555 - 210 = 1240332112531 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 206375051 + ... + 206381060.

It is an arithmetic number, because the mean of its divisors is an integer number (186359384568).

Almost surely, 21240332113555 is an apocalyptic number.

1240332113555 is a deficient number, since it is larger than the sum of its proper divisors (250542962989).

1240332113555 is an equidigital number, since it uses as much as digits as its factorization.

1240332113555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 412756717.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 1240332113555 its reverse (5553112330421), we get a palindrome (6793444443976).

The spelling of 1240332113555 in words is "one trillion, two hundred forty billion, three hundred thirty-two million, one hundred thirteen thousand, five hundred fifty-five".

Divisors: 1 5 601 3005 412756111 2063780555 248066422711 1240332113555