Base | Representation |
---|---|
bin | 10111000110101011… |
… | …01101010001101111 |
3 | 1012000110102012000012 |
4 | 23203111231101233 |
5 | 200400414144403 |
6 | 5410501523435 |
7 | 616245466061 |
oct | 134325552157 |
9 | 35013365005 |
10 | 12404053103 |
11 | 5295845762 |
12 | 24a211357b |
13 | 1228a94bc0 |
14 | 859559731 |
15 | 4c8e84ed8 |
hex | 2e356d46f |
12404053103 has 4 divisors (see below), whose sum is σ = 13358211048. Its totient is φ = 11449895160.
The previous prime is 12404053073. The next prime is 12404053141. The reversal of 12404053103 is 30135040421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12404053103 - 214 = 12404036719 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12404053163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 477078953 + ... + 477078978.
It is an arithmetic number, because the mean of its divisors is an integer number (3339552762).
Almost surely, 212404053103 is an apocalyptic number.
12404053103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12404053103 is a deficient number, since it is larger than the sum of its proper divisors (954157945).
12404053103 is an equidigital number, since it uses as much as digits as its factorization.
12404053103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 954157944.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 12404053103 its reverse (30135040421), we get a palindrome (42539093524).
The spelling of 12404053103 in words is "twelve billion, four hundred four million, fifty-three thousand, one hundred three".
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