Base | Representation |
---|---|
bin | 10111000110101101… |
… | …10001011000001101 |
3 | 1012000110221100122101 |
4 | 23203112301120031 |
5 | 200401002111140 |
6 | 5410511515101 |
7 | 616251040240 |
oct | 134326613015 |
9 | 35013840571 |
10 | 12404332045 |
11 | 5295a16296 |
12 | 24a2228a91 |
13 | 1228b61b61 |
14 | 8595cd257 |
15 | 4c8edc99a |
hex | 2e35b160d |
12404332045 has 16 divisors (see below), whose sum is σ = 17065335168. Its totient is φ = 8478987840.
The previous prime is 12404332007. The next prime is 12404332051. The reversal of 12404332045 is 54023340421.
It is a happy number.
12404332045 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12404332045 - 217 = 12404200973 is a prime.
It is a super-2 number, since 2×124043320452 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 547911 + ... + 570100.
It is an arithmetic number, because the mean of its divisors is an integer number (1066583448).
Almost surely, 212404332045 is an apocalyptic number.
It is an amenable number.
12404332045 is a deficient number, since it is larger than the sum of its proper divisors (4661003123).
12404332045 is a wasteful number, since it uses less digits than its factorization.
12404332045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1118340.
The product of its (nonzero) digits is 11520, while the sum is 28.
Adding to 12404332045 its reverse (54023340421), we get a palindrome (66427672466).
The spelling of 12404332045 in words is "twelve billion, four hundred four million, three hundred thirty-two thousand, forty-five".
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