12411001433 has 4 divisors (see below), whose sum is σ = 12411232308. Its totient is φ = 12410770560.

The previous prime is 12411001429. The next prime is 12411001469. The reversal of 12411001433 is 33410011421.

12411001433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33410011421 = 853 ⋅39167657.

It can be written as a sum of positive squares in 2 ways, for example, as 3047923264 + 9363078169 = 55208^2 + 96763^2 .

It is a cyclic number.

It is not a de Polignac number, because 12411001433 - 2² = 12411001429 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12411001483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12353 + ... + 158033.

It is an arithmetic number, because the mean of its divisors is an integer number (3102808077).

Almost surely, 2^12411001433 is an apocalyptic number.

It is an amenable number.

12411001433 is a deficient number, since it is larger than the sum of its proper divisors (230875).

12411001433 is an equidigital number, since it uses as much as digits as its factorization.

12411001433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 230874.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 12411001433 its reverse (33410011421), we get a palindrome (45821012854).

The spelling of 12411001433 in words is "twelve billion, four hundred eleven million, one thousand, four hundred thirty-three".