1241140100111 has 4 divisors (see below), whose sum is σ = 1314148341312. Its totient is φ = 1168131858912.

The previous prime is 1241140100089. The next prime is 1241140100171. The reversal of 1241140100111 is 1110010411421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1241140100111 - 2¹⁸ = 1241139837967 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 73008241183 = 1241140100111 / (1 + 2 + 4 + 1 + 1 + 4 + 0 + 1 + 0 + 0 + 1 + 1 + 1).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1241140100111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1241140100171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36504120575 + ... + 36504120608.

It is an arithmetic number, because the mean of its divisors is an integer number (328537085328).

Almost surely, 2^{1241140100111} is an apocalyptic number.

1241140100111 is a deficient number, since it is larger than the sum of its proper divisors (73008241201).

1241140100111 is an equidigital number, since it uses as much as digits as its factorization.

1241140100111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 73008241200.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 1241140100111 its reverse (1110010411421), we get a palindrome (2351150511532).

The spelling of 1241140100111 in words is "one trillion, two hundred forty-one billion, one hundred forty million, one hundred thousand, one hundred eleven".