12412040320031 has 4 divisors (see below), whose sum is σ = 13540407621864. Its totient is φ = 11283673018200.

The previous prime is 12412040320007. The next prime is 12412040320037. The reversal of 12412040320031 is 13002304021421.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12412040320031 - 2²⁶ = 12411973211167 is a prime.

It is a super-2 number, since 2×12412040320031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12412040319979 and 12412040320006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12412040320037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 564183650900 + ... + 564183650921.

It is an arithmetic number, because the mean of its divisors is an integer number (3385101905466).

Almost surely, 2^{12412040320031} is an apocalyptic number.

12412040320031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

12412040320031 is a deficient number, since it is larger than the sum of its proper divisors (1128367301833).

12412040320031 is a wasteful number, since it uses less digits than its factorization.

12412040320031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1128367301832.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12412040320031 its reverse (13002304021421), we get a palindrome (25414344341452).

The spelling of 12412040320031 in words is "twelve trillion, four hundred twelve billion, forty million, three hundred twenty thousand, thirty-one".