Base | Representation |
---|---|
bin | 10010000100001011110… |
… | …101100111011011011111 |
3 | 11101200101101012020001010 |
4 | 102010023311213123133 |
5 | 130314434200344210 |
6 | 2350151144350303 |
7 | 155456100122421 |
oct | 22041365473337 |
9 | 4350341166033 |
10 | 1241444153055 |
11 | 439547950757 |
12 | 180725175393 |
13 | 900b59079b2 |
14 | 4412c81c811 |
15 | 2245d389920 |
hex | 1210bd676df |
1241444153055 has 8 divisors (see below), whose sum is σ = 1986310644912. Its totient is φ = 662103548288.
The previous prime is 1241444153039. The next prime is 1241444153063. The reversal of 1241444153055 is 5503514441421.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1241444153055 - 24 = 1241444153039 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41381471754 + ... + 41381471783.
It is an arithmetic number, because the mean of its divisors is an integer number (248288830614).
Almost surely, 21241444153055 is an apocalyptic number.
1241444153055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1241444153055 is a deficient number, since it is larger than the sum of its proper divisors (744866491857).
1241444153055 is an equidigital number, since it uses as much as digits as its factorization.
1241444153055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82762943545.
The product of its (nonzero) digits is 192000, while the sum is 39.
Adding to 1241444153055 its reverse (5503514441421), we get a palindrome (6744958594476).
The spelling of 1241444153055 in words is "one trillion, two hundred forty-one billion, four hundred forty-four million, one hundred fifty-three thousand, fifty-five".
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