Base | Representation |
---|---|
bin | 10010000101101111001… |
… | …101011100010011100011 |
3 | 11101211200120022021011010 |
4 | 102011233031130103203 |
5 | 130331343000441311 |
6 | 2351024422152003 |
7 | 155545313034444 |
oct | 22055715342343 |
9 | 4354616267133 |
10 | 1243111343331 |
11 | 43a222a44460 |
12 | 180b0b582603 |
13 | 902c0137410 |
14 | 4424a0032cb |
15 | 2250990bda6 |
hex | 1216f35c4e3 |
1243111343331 has 16 divisors (see below), whose sum is σ = 1947251335680. Its totient is φ = 695446905120.
The previous prime is 1243111343297. The next prime is 1243111343363. The reversal of 1243111343331 is 1333431113421.
It is a happy number.
It is not a de Polignac number, because 1243111343331 - 222 = 1243107149027 is a prime.
It is a super-2 number, since 2×12431113433312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1243111343381) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1448847291 + ... + 1448848148.
It is an arithmetic number, because the mean of its divisors is an integer number (121703208480).
Almost surely, 21243111343331 is an apocalyptic number.
1243111343331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1243111343331 is a deficient number, since it is larger than the sum of its proper divisors (704139992349).
1243111343331 is a wasteful number, since it uses less digits than its factorization.
1243111343331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2897695466.
The product of its digits is 7776, while the sum is 30.
Adding to 1243111343331 its reverse (1333431113421), we get a palindrome (2576542456752).
The spelling of 1243111343331 in words is "one trillion, two hundred forty-three billion, one hundred eleven million, three hundred forty-three thousand, three hundred thirty-one".
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