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12434342113 = 171051695939
BaseRepresentation
bin10111001010010010…
…10000000011100001
31012002120102000201101
423211021100003201
5200431142421423
65413503034401
7620064110164
oct134511200341
935076360641
1012434342113
1153009532a6
1224b029ba01
13123213b5ab
1485d5a1adb
154cb9697ad
hex2e52500e1

12434342113 has 8 divisors (see below), whose sum is σ = 13178319840. Its totient is φ = 11691758400.

The previous prime is 12434342071. The next prime is 12434342119. The reversal of 12434342113 is 31124343421.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12434342113 is a prime.

It is a super-2 number, since 2×124343421132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12434342119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 330103 + ... + 365836.

It is an arithmetic number, because the mean of its divisors is an integer number (1647289980).

Almost surely, 212434342113 is an apocalyptic number.

It is an amenable number.

12434342113 is a deficient number, since it is larger than the sum of its proper divisors (743977727).

12434342113 is a wasteful number, since it uses less digits than its factorization.

12434342113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 697007.

The product of its digits is 6912, while the sum is 28.

Adding to 12434342113 its reverse (31124343421), we get a palindrome (43558685534).

The spelling of 12434342113 in words is "twelve billion, four hundred thirty-four million, three hundred forty-two thousand, one hundred thirteen".

Divisors: 1 17 1051 17867 695939 11830963 731431889 12434342113