Base | Representation |
---|---|
bin | 10111001010111110… |
… | …10111110011011111 |
3 | 1012002222022122022211 |
4 | 23211133113303133 |
5 | 200434134003043 |
6 | 5414231221251 |
7 | 620164311502 |
oct | 134537276337 |
9 | 35088278284 |
10 | 12440141023 |
11 | 5304154092 |
12 | 24b2217827 |
13 | 12333bbbbb |
14 | 860271139 |
15 | 4cc212a9d |
hex | 2e57d7cdf |
12440141023 has 4 divisors (see below), whose sum is σ = 12448061208. Its totient is φ = 12432220840.
The previous prime is 12440140919. The next prime is 12440141039. The reversal of 12440141023 is 32014104421.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12440141023 is a prime.
It is a Duffinian number.
It is a plaindrome in base 13.
It is a junction number, because it is equal to n+sod(n) for n = 12440140985 and 12440141003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12440141723) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3957736 + ... + 3960877.
It is an arithmetic number, because the mean of its divisors is an integer number (3112015302).
Almost surely, 212440141023 is an apocalyptic number.
12440141023 is a deficient number, since it is larger than the sum of its proper divisors (7920185).
12440141023 is an equidigital number, since it uses as much as digits as its factorization.
12440141023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7920184.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 12440141023 its reverse (32014104421), we get a palindrome (44454245444).
The spelling of 12440141023 in words is "twelve billion, four hundred forty million, one hundred forty-one thousand, twenty-three".
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