Base | Representation |
---|---|
bin | 10010000110100101000… |
… | …001010110110000010111 |
3 | 11101221000111002022120202 |
4 | 102012211001112300113 |
5 | 130340220110111120 |
6 | 2351254152251115 |
7 | 155606554521101 |
oct | 22064501266027 |
9 | 4357014068522 |
10 | 1244014144535 |
11 | 43a64660a358 |
12 | 1811219a0a9b |
13 | 904051a1b06 |
14 | 442d3c8c571 |
15 | 2255dcdd875 |
hex | 121a5056c17 |
1244014144535 has 4 divisors (see below), whose sum is σ = 1492816973448. Its totient is φ = 995211315624.
The previous prime is 1244014144519. The next prime is 1244014144579. The reversal of 1244014144535 is 5354414104421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1244014144535 - 24 = 1244014144519 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124401414449 + ... + 124401414458.
It is an arithmetic number, because the mean of its divisors is an integer number (373204243362).
Almost surely, 21244014144535 is an apocalyptic number.
1244014144535 is a deficient number, since it is larger than the sum of its proper divisors (248802828913).
1244014144535 is an equidigital number, since it uses as much as digits as its factorization.
1244014144535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 248802828912.
The product of its (nonzero) digits is 153600, while the sum is 38.
Adding to 1244014144535 its reverse (5354414104421), we get a palindrome (6598428248956).
The spelling of 1244014144535 in words is "one trillion, two hundred forty-four billion, fourteen million, one hundred forty-four thousand, five hundred thirty-five".
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