Base | Representation |
---|---|
bin | 10010000111101011101… |
… | …101011011000001111100 |
3 | 11102001002010200011200210 |
4 | 102013223231123001330 |
5 | 130400132211222000 |
6 | 2352011555352420 |
7 | 155651135140425 |
oct | 22075355330174 |
9 | 4361063604623 |
10 | 1245200101500 |
11 | 4400a4aa4383 |
12 | 1813b2bb2710 |
13 | 90563aba3b4 |
14 | 443a75a464c |
15 | 225ccea3350 |
hex | 121ebb5b07c |
1245200101500 has 96 divisors (see below), whose sum is σ = 3629477359872. Its totient is φ = 331737000000.
The previous prime is 1245200101487. The next prime is 1245200101513. The reversal of 1245200101500 is 51010025421.
It is an interprime number because it is at equal distance from previous prime (1245200101487) and next prime (1245200101513).
It is a super-2 number, since 2×12452001015002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1181575 + ... + 1971425.
It is an arithmetic number, because the mean of its divisors is an integer number (37807055832).
Almost surely, 21245200101500 is an apocalyptic number.
1245200101500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1245200101500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1814738679936).
1245200101500 is an abundant number, since it is smaller than the sum of its proper divisors (2384277258372).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1245200101500 is a wasteful number, since it uses less digits than its factorization.
1245200101500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 790924 (or 790912 counting only the distinct ones).
The product of its (nonzero) digits is 400, while the sum is 21.
Adding to 1245200101500 its reverse (51010025421), we get a palindrome (1296210126921).
The spelling of 1245200101500 in words is "one trillion, two hundred forty-five billion, two hundred million, one hundred one thousand, five hundred".
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