Base | Representation |
---|---|
bin | 10010001101011001001… |
… | …001110111010011101111 |
3 | 11102121220102111100012220 |
4 | 102031121021313103233 |
5 | 131000211244204244 |
6 | 2354504215130423 |
7 | 156256104024324 |
oct | 22153111672357 |
9 | 4377812440186 |
10 | 1251331241199 |
11 | 442760955386 |
12 | 182624373a13 |
13 | 910000b0600 |
14 | 447c998cb4b |
15 | 2283b392319 |
hex | 123592774ef |
1251331241199 has 12 divisors (see below), whose sum is σ = 1806655757256. Its totient is φ = 770049994272.
The previous prime is 1251331241191. The next prime is 1251331241201. The reversal of 1251331241199 is 9911421331521.
It is not a de Polignac number, because 1251331241199 - 23 = 1251331241191 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1251331241199.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1251331241191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1234053972 + ... + 1234054985.
It is an arithmetic number, because the mean of its divisors is an integer number (150554646438).
Almost surely, 21251331241199 is an apocalyptic number.
1251331241199 is a deficient number, since it is larger than the sum of its proper divisors (555324516057).
1251331241199 is a wasteful number, since it uses less digits than its factorization.
1251331241199 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2468108986 (or 2468108973 counting only the distinct ones).
The product of its digits is 58320, while the sum is 42.
The spelling of 1251331241199 in words is "one trillion, two hundred fifty-one billion, three hundred thirty-one million, two hundred forty-one thousand, one hundred ninety-nine".
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