Base | Representation |
---|---|
bin | 1011011000011011100010… |
… | …0001001000001001011000 |
3 | 1122022100200112220212100210 |
4 | 2312012320201020021120 |
5 | 3120013324332100422 |
6 | 42341001211131120 |
7 | 2431062620002233 |
oct | 266067041101130 |
9 | 48270615825323 |
10 | 12514335425112 |
11 | 3a95333110374 |
12 | 14a1441743aa0 |
13 | 6ca13479b711 |
14 | 3139a8a7041a |
15 | 16a7d734210c |
hex | b61b8848258 |
12514335425112 has 32 divisors (see below), whose sum is σ = 31286979658800. Its totient is φ = 4171292995584.
The previous prime is 12514335425047. The next prime is 12514335425147. The reversal of 12514335425112 is 21152453341521.
It is a super-2 number, since 2×125143354251122 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8836437 + ... + 10154372.
Almost surely, 212514335425112 is an apocalyptic number.
12514335425112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12514335425112 is an abundant number, since it is smaller than the sum of its proper divisors (18772644233688).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12514335425112 is a wasteful number, since it uses less digits than its factorization.
12514335425112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19018275 (or 19018271 counting only the distinct ones).
The product of its digits is 144000, while the sum is 39.
Adding to 12514335425112 its reverse (21152453341521), we get a palindrome (33666788766633).
The spelling of 12514335425112 in words is "twelve trillion, five hundred fourteen billion, three hundred thirty-five million, four hundred twenty-five thousand, one hundred twelve".
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