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12517137156701 is a prime number
BaseRepresentation
bin1011011000100101111110…
…0000111000101001011101
31122022121220210212120120102
42312021133200320221131
53120040044103003301
642342143214030445
72431222220222012
oct266113740705135
948277823776512
1012517137156701
113a96540670821
1214a1aa3aa8425
136ca490083b68
14313b92bc5709
1516a8ed2beb6b
hexb625f838a5d

12517137156701 has 2 divisors, whose sum is σ = 12517137156702. Its totient is φ = 12517137156700.

The previous prime is 12517137156653. The next prime is 12517137156703. The reversal of 12517137156701 is 10765173171521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11151391996900 + 1365745159801 = 3339370^2 + 1168651^2 .

It is a cyclic number.

It is not a de Polignac number, because 12517137156701 - 214 = 12517137140317 is a prime.

Together with 12517137156703, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12517137156703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6258568578350 + 6258568578351.

It is an arithmetic number, because the mean of its divisors is an integer number (6258568578351).

Almost surely, 212517137156701 is an apocalyptic number.

It is an amenable number.

12517137156701 is a deficient number, since it is larger than the sum of its proper divisors (1).

12517137156701 is an equidigital number, since it uses as much as digits as its factorization.

12517137156701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 308700, while the sum is 47.

The spelling of 12517137156701 in words is "twelve trillion, five hundred seventeen billion, one hundred thirty-seven million, one hundred fifty-six thousand, seven hundred one".