Base | Representation |
---|---|
bin | 10010001110000100111… |
… | …110011001111110100101 |
3 | 11102200210122220001111020 |
4 | 102032010332121332211 |
5 | 131003213001404411 |
6 | 2355105201001353 |
7 | 156313242045405 |
oct | 22160476317645 |
9 | 4380718801436 |
10 | 1252066434981 |
11 | 442aa895234a |
12 | 1827aa623259 |
13 | 910b94c2a0b |
14 | 44859488805 |
15 | 22880bb7606 |
hex | 12384f99fa5 |
1252066434981 has 4 divisors (see below), whose sum is σ = 1669421913312. Its totient is φ = 834710956652.
The previous prime is 1252066434979. The next prime is 1252066435013. The reversal of 1252066434981 is 1894346602521.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1252066434981 - 21 = 1252066434979 is a prime.
It is a super-2 number, since 2×12520664349812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1252066436981) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208677739161 + ... + 208677739166.
It is an arithmetic number, because the mean of its divisors is an integer number (417355478328).
Almost surely, 21252066434981 is an apocalyptic number.
It is an amenable number.
1252066434981 is a deficient number, since it is larger than the sum of its proper divisors (417355478331).
1252066434981 is an equidigital number, since it uses as much as digits as its factorization.
1252066434981 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 417355478330.
The product of its (nonzero) digits is 2488320, while the sum is 51.
The spelling of 1252066434981 in words is "one trillion, two hundred fifty-two billion, sixty-six million, four hundred thirty-four thousand, nine hundred eighty-one".
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