1252342031 has 4 divisors (see below), whose sum is σ = 1252415952. Its totient is φ = 1252268112.

The previous prime is 1252342027. The next prime is 1252342033. The reversal of 1252342031 is 1302432521.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1302432521 = 13 ⋅100187117.

It is a cyclic number.

It is not a de Polignac number, because 1252342031 - 2² = 1252342027 is a prime.

It is a super-2 number, since 2×1252342031² = 3136721125218409922, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1252341988 and 1252342006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1252342033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2486 + ... + 50108.

It is an arithmetic number, because the mean of its divisors is an integer number (313103988).

Almost surely, 2^1252342031 is an apocalyptic number.

1252342031 is a deficient number, since it is larger than the sum of its proper divisors (73921).

1252342031 is an equidigital number, since it uses as much as digits as its factorization.

1252342031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 73920.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 1252342031 is about 35388.4448796496. Note that the first 3 decimals coincide. The cubic root of 1252342031 is about 1077.8896923260.

Adding to 1252342031 its reverse (1302432521), we get a palindrome (2554774552).

The spelling of 1252342031 in words is "one billion, two hundred fifty-two million, three hundred forty-two thousand, thirty-one".