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12524114331013 = 39251931907027
BaseRepresentation
bin1011011000111111111101…
…1000101100010110000101
31122100021221001122202101211
42312033333120230112011
53120143341232043023
642345255415051421
72431560141223045
oct266177730542605
948307831582354
1012524114331013
113a994a104508a
1214a3310670b71
136cb03272747c
143142556bd725
1516abaaacaa0d
hexb63ff62c585

12524114331013 has 4 divisors (see below), whose sum is σ = 12524146630560. Its totient is φ = 12524082031468.

The previous prime is 12524114330971. The next prime is 12524114331041. The reversal of 12524114331013 is 31013341142521.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12524114331013 - 29 = 12524114330501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12524114331073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15560995 + ... + 16346032.

It is an arithmetic number, because the mean of its divisors is an integer number (3131036657640).

Almost surely, 212524114331013 is an apocalyptic number.

It is an amenable number.

12524114331013 is a deficient number, since it is larger than the sum of its proper divisors (32299547).

12524114331013 is an equidigital number, since it uses as much as digits as its factorization.

12524114331013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32299546.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 12524114331013 its reverse (31013341142521), we get a palindrome (43537455473534).

The spelling of 12524114331013 in words is "twelve trillion, five hundred twenty-four billion, one hundred fourteen million, three hundred thirty-one thousand, thirteen".

Divisors: 1 392519 31907027 12524114331013