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125270447 is a prime number
BaseRepresentation
bin1110111011101…
…11100110101111
322201201101202012
413131313212233
5224032123242
620232551435
73050531651
oct735674657
9281641665
10125270447
11647915a5
1235b5257b
131cc50b33
14128cc6d1
15aee7282
hex77779af

125270447 has 2 divisors, whose sum is σ = 125270448. Its totient is φ = 125270446.

The previous prime is 125270413. The next prime is 125270479. The reversal of 125270447 is 744072521.

It is an a-pointer prime, because the next prime (125270479) can be obtained adding 125270447 to its sum of digits (32).

It is a strong prime.

It is an emirp because it is prime and its reverse (744072521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125270447 - 210 = 125269423 is a prime.

It is a Chen prime.

It is a plaindrome in base 16.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125270407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62635223 + 62635224.

It is an arithmetic number, because the mean of its divisors is an integer number (62635224).

Almost surely, 2125270447 is an apocalyptic number.

125270447 is a deficient number, since it is larger than the sum of its proper divisors (1).

125270447 is an equidigital number, since it uses as much as digits as its factorization.

125270447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15680, while the sum is 32.

The square root of 125270447 is about 11192.4281101109. The cubic root of 125270447 is about 500.3603362532.

The spelling of 125270447 in words is "one hundred twenty-five million, two hundred seventy thousand, four hundred forty-seven".