Base | Representation |
---|---|
bin | 10010001110111111110… |
… | …011100010010110000111 |
3 | 11102210100110010011210002 |
4 | 102032333303202112013 |
5 | 131012223140111130 |
6 | 2355351135551515 |
7 | 156346555341236 |
oct | 22167763422607 |
9 | 4383313104702 |
10 | 1253053441415 |
11 | 443465000946 |
12 | 182a2508b59b |
13 | 91215b308a9 |
14 | 449105b2b1d |
15 | 228dc67db45 |
hex | 123bfce2587 |
1253053441415 has 4 divisors (see below), whose sum is σ = 1503664129704. Its totient is φ = 1002442753128.
The previous prime is 1253053441391. The next prime is 1253053441433. The reversal of 1253053441415 is 5141443503521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1253053441415 - 210 = 1253053440391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125305344137 + ... + 125305344146.
It is an arithmetic number, because the mean of its divisors is an integer number (375916032426).
Almost surely, 21253053441415 is an apocalyptic number.
1253053441415 is a deficient number, since it is larger than the sum of its proper divisors (250610688289).
1253053441415 is an equidigital number, since it uses as much as digits as its factorization.
1253053441415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 250610688288.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 1253053441415 its reverse (5141443503521), we get a palindrome (6394496944936).
The spelling of 1253053441415 in words is "one trillion, two hundred fifty-three billion, fifty-three million, four hundred forty-one thousand, four hundred fifteen".
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