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1253053441415 = 5250610688283
BaseRepresentation
bin10010001110111111110…
…011100010010110000111
311102210100110010011210002
4102032333303202112013
5131012223140111130
62355351135551515
7156346555341236
oct22167763422607
94383313104702
101253053441415
11443465000946
12182a2508b59b
1391215b308a9
14449105b2b1d
15228dc67db45
hex123bfce2587

1253053441415 has 4 divisors (see below), whose sum is σ = 1503664129704. Its totient is φ = 1002442753128.

The previous prime is 1253053441391. The next prime is 1253053441433. The reversal of 1253053441415 is 5141443503521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1253053441415 - 210 = 1253053440391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125305344137 + ... + 125305344146.

It is an arithmetic number, because the mean of its divisors is an integer number (375916032426).

Almost surely, 21253053441415 is an apocalyptic number.

1253053441415 is a deficient number, since it is larger than the sum of its proper divisors (250610688289).

1253053441415 is an equidigital number, since it uses as much as digits as its factorization.

1253053441415 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 250610688288.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 1253053441415 its reverse (5141443503521), we get a palindrome (6394496944936).

The spelling of 1253053441415 in words is "one trillion, two hundred fifty-three billion, fifty-three million, four hundred forty-one thousand, four hundred fifteen".

Divisors: 1 5 250610688283 1253053441415