Base | Representation |
---|---|
bin | 10010001111001001011… |
… | …000001011101101111000 |
3 | 11102210202122022120201221 |
4 | 102033021120023231320 |
5 | 131013040243334000 |
6 | 2355415114121424 |
7 | 156353545414363 |
oct | 22171130135570 |
9 | 4383678276657 |
10 | 1253214043000 |
11 | 443537724227 |
12 | 182a6aa20274 |
13 | 912401a210a |
14 | 44927a5b0da |
15 | 228eb80461a |
hex | 123c960bb78 |
1253214043000 has 32 divisors (see below), whose sum is σ = 2932520862960. Its totient is φ = 501285616800.
The previous prime is 1253214042973. The next prime is 1253214043027. The reversal of 1253214043000 is 3404123521.
It is an interprime number because it is at equal distance from previous prime (1253214042973) and next prime (1253214043027).
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 626606022 + ... + 626608021.
Almost surely, 21253214043000 is an apocalyptic number.
1253214043000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1253214043000 is an abundant number, since it is smaller than the sum of its proper divisors (1679306819960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1253214043000 is a wasteful number, since it uses less digits than its factorization.
1253214043000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1253214064 (or 1253214050 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 1253214043000 its reverse (3404123521), we get a palindrome (1256618166521).
The spelling of 1253214043000 in words is "one trillion, two hundred fifty-three billion, two hundred fourteen million, forty-three thousand".
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